What can be inferred from the following equation?

$N a_{2} S O_{4} (a q) + B a C l_{2} (a q) \to B a S O_{4} (s) + 2 N a C l (a q)$

(i) It is a double displacement reaction.

(ii) It is a precipitation reaction.

(iii) It is a decomposition reaction.

(iv) $B a S O_{4}$ is soluble in water

(v) $B a S O_{4}$ is precipitate.

(vi) $N a C l$ dissolves in water.

(i),(ii), (iv), (vi).

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(i),(iii), (v), (vi).

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(ii),(iii), (iv), (vi)

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(i),(ii), (v), (vi).

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Solution

The correct option is D
(i),(ii), (v), (vi).

$N a_{2} S O_{4} (a q) + B a C l_{2} (a q) \to B a S O_{4} (s) + 2 N a C l (a q)$

In above reaction, $N a^{+}$ and $B a^{2 +}$ ions are exchanged between the reactants, hence it is a double displacement reaction.

The product $B a S O_{4}$ is not soluble in water, hence is a precipitate. This reaction is also called precipitation reaction due to the formation of a precipitate. $N a C l$ dissolves in water.

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Similar questions

What can be inferred from the following equation?

$N a_{2} S O_{4} (a q) + B a C l_{2} (a q) \to B a S O_{4} (s) + 2 N a C l (a q)$

(i) It is a displacement reaction.

(ii) It is a precipitation reaction.

(iii) It is a double decomposition reaction.

(iv) $B a S O_{4}$ is soluble in water

(v) $B a S O_{4}$ is a precipitate.

(vi) NaCl dissolves in water.

What can be inferred from the following equation?

${Na}_{2} {SO}_{4} (aq) + {BaCl}_{2} (aq) \to {BaSO}_{4} (s) + 2 NaCl (aq)$ .

N a_{2} S O_{4}

B a S O_{4}

B a S O_{4}

B a S O_{4}

2.33 \times 10^{- 3} g L^{- 1}

B a S O_{4} = 233

B a C l_{2} (a q) + N a_{2} S O_{4} (a q) \to B a S O_{4} (s) + 2 N a C l (a q)

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