What is correct formulation of Hardy-Weinberg law- p-2 - pq - q-2 - 1- p-2 - 2pq - q-2 - 1- p-2 - 2pq - q-2 - 0- p-2 - pq - q-2 - 0-

The correct option is B p^2 + 2pq + q^2 = 1 The Hardy Weinberg equation is given by,p2 #160;+ 2pq + q2 #160;= 1Here, p and q represent the individual ...

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Standard XII

Biology

What Are Alleles

What is corre...

Question

What is correct formulation of Hardy-Weinberg law?

p^{2} + 2 p q + q^{2} = 1

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p^{2} + p q + q^{2} = 1

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p^{2} + 2 p q + q^{2} = 0

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p^{2} + p q + q^{2} = 0

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Solution

The correct option is B $p^{2} + 2 p q + q^{2} = 1$
The Hardy-Weinberg equation is given by,
p2 + 2pq + q2 = 1
Here, p and q represent the individual allele frequencies.
Therefore, p2= frequency of homozygous condition represented by p.
q2= frequency of homozygous alleles represented by q.
2pq = frequency of heterozygous condition.
So, the correct answer is 'p2 + 2pq + q2 = 1'

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Similar questions

Subtract:

p^{2} - 2 p q + q^{2}

from

p^{2} + 2 p q - q^{2}

Q. Select the correct option with respect to the Hardy-Weinberg equation,

p^{2} + 2 p q + q^{2} = 1

What does $p^{2}$ in the below mentioned Hardy - Weinberg equation indicate?

${(p + q)}^{2} = p^{2} + 2 pq + q^{2}$

(p + q)^{2} = p^{2} + 2 p q + q^{2} = 1

represents an equation used in:

p^{2} + 2 p q + q^{2} = 1

. Explain the algebraic equation on the basis of Hardy Weinberg's principle.

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