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Question

What is sum of all the isomeric aromatic compounds of the formula B3N3HnCl(6n) (isomeric chloro substituted inorganic benzene), where n belongs to [0,6] ?

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Solution

B3N3H6=1 and B3N3H5Cl=2

B3N3H4Cl2=4

B3N3H3Cl3=6

B3N3H2Cl4=4

B3N3HCl5=2 and B3N3Cl6=1

Total 1 + 2 + 4 + 6 + 4 + 2 + 1 = 20

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