What is the concentration of nitrate ions if equal volumes of $0.1MAgN{O}_3$ and $0.1MNaCl$ are mixed together?

The correct option is C $0.05$ M
Given,

$0.1M$ $AgN{O}_3$ & $0.1M$ $NaCl$ are mixed together.

We know,

$0.1M$ $AgN{O}_3$ solution contains

$0.1$ moles of $A{g}^{+}$ & $0.1$ moles of $N{O}_3^{-}$ in $1000ml$ of solution.

$0.1M$ $NaCl$ solution contains

$0.1$ moles of $N{a}^{+}$ & $0.1$ moles of $C{l}^{-}$ ions in $1000ml$ of solution.

$\therefore$ Total moles of $N{O}_3^{-}=0.1$

The total volume of solution=$2000ml$

$\therefore$ Molarity of $N{O}_3^{-}$ ions=$\frac{molesofN{O}_3^{-}}{VolumeofsolutioninL}$

$=\frac{0.1moles}{2L}$

$=0.05M$.

Hence, the correct option is $C$