What is the correct formulation of Hardy-Weinberg law?

p^{2} + 2 p q + q^{2} = 1

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p^{2} + p q + q^{2} = 0

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p^{2} + p q + q^{2} = 1

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p^{2} + 2 p q + q^{2} = 0

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Solution

The correct option is A $p^{2} + 2 p q + q^{2} = 1$
The Hardy-Weinberg equation used to determine genotype frequencies is:

$p^{2} + 2 p q + q^{2} = 1$ .

Where $p^{2}$ represents the frequency of the homozygous dominant genotype.

$2 p q$ represents the frequency of the heterozygous genotype.

$q^{2}$ represents the frequency of the homozygous recessive genotype.

Hence the correct option is
a. $p^{2} + 2 p q + q^{2} = 1$

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