What is the electronic configuration for an $F e (I I I)$ ion in its ground state?

[A r] 3 d^{5}

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[A r] 3 d^{6}

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[A r] 4 s^{2} 3 d^{3}

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[A r] 4 s^{2} 3 d^{6}

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Solution

The correct option is A $[A r] 3 d^{5}$
Electronic configuration of $F e$
$F e = [A r] 3 d^{6} 4 s^{2}$

so Electronic configuration of $F e (I I I)$
$F e^{+ 3} = [A r] 3 d^{5}$

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