What is the mass of 4 moles of aluminium atoms (Atomic mass of aluminium = 27)

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Solution

We know that
Mole = $\frac{G i v e n m a s s}{m o l a r m a s s} = M o l e o f A l u m i n i u m a t o m = \frac{g i v e n m a s s}{a t o m i c m a s s} M a s s = M o l e \times A t o m i c m a s s = 4 \times 27 = 108 g$

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