What is the percentage change in the momentum of the body, if the mass of a body is doubled and its velocity is reduced by half?

The correct option is A

0 %

Step 1: Momentum

1. In the motion of a body momentum is a quantity that is measured as a product of the mass and velocity of the body.
2. Mathematically the momentum is represented as$p=mv$ where p is the momentum, m is the mass of the body and v is the velocity of the body.

Step 2: Calculation of change in momentum

1. If the mass of the body is doubled, the new mass will be $2m$.
2. If the velocity of the body is reduced by half, the new velocity will be$v-\frac{v}{2}=\frac{v}{2}$.
3. Now the new momentum of the body will be$p\text{'}=2m\times \frac{v}{2}=mv$
4. The change in momentum will be$p\text{'}-p=mv-mv=0$.
5. As there is no change in momentum of the body, so we can say that the percentage change in the momentum of the body will be 0%.

Hence, the percentage change in the momentum of the body will be 0 %.