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Question
What is the smallest number which when increased by 5 is divisible by 36, 63 and 108?
What is the smallest number which when increased by 5 is divisible by 36, 63 and 108?
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Solution
The correct option is B 751
Calculate the LCM of 36, 63 and 108 which would come out to be 756, so the smallest number is 751 which when increased by 5 is 756.
751
Calculate the LCM of 36, 63 and 108 which would come out to be 756, so the smallest number is 751 which when increased by 5 is 756.
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