What mass of $Na$ will contain $6.023\times {10}^{23}$ number of atoms?

The correct option is A $23$ g
One mole of each substance contains $N_A=6.023\times {10}^{23}$ atoms. Here $N_A$ = Avogadro number.

Mass of one mole of atoms = Molar mass

So, the mass of one mole of $Na$ = $23$ g = $6.023\times {10}^{23}$ number of atoms. (Atomic mass of $Na$ = $23$ u and molar mass is numerically equal to the atomic mass)
Hence, option A is correct.