What number should be added in $\frac{-7}{8}$ to get $\frac{4}{9}$

Let the number to be added be $x$

According to question,

$\frac{-7}{8}+x=\frac{4}{9}$

$\Rightarrow x=\frac{4}{9}+\frac{7}{8}$

$\Rightarrow x=\frac{32+63}{8\times 9}$

$\therefore x=\frac{95}{72}$