What will be the kinetic energy of a body when its mass is made four times and the velocity is doubled?

Open in App

Solution

Step 1: Given data
$I n i t i a l m a s s = m (s a y), I n i t i a l v e l o c i t y = v (s a y), F i n a l m a s s = 4 m, F i n a l v e l o c i t y = 2 v$
To find the new kinetic energy.
Step 2: Formula used
The kinetic energy of an object of mass $m$ and speed $v$ is given by,
$K . E = \frac{1}{2} m v^{2}$
Step 3: Calculation
$I n i t i a l k i n e t i c e n e r g y (K) = \frac{1}{2} m v^{2} F i n a l k i n e t i c e n e r g y = \frac{1}{2} \times (4 m) \times {(2 v)}^{2} = \frac{1}{2} \times 4 m \times 4 v^{2} = 16 \times \frac{1}{2} m v^{2} = 16 K$
Hence, the kinetic energy will be 16 times the initial kinetic energy.

Suggest Corrections

Similar questions

What will be the kinetic energy of a body when its mass is made four times and the velocity is doubled?

The kinetic energy of an object of mass, m moving with a velocity of 5 m s⁻¹ is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

Q. Question 3
The kinetic energy of an object of mass, m moving with a velocity of

5 m s^{- 1}

is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

A body of mass $5 k g$ moving with a velocity of $10 m / s$ . What will be the ratio of its kinetic energy and final kinetic energy if the mass of the body is doubled and its velocity is halved.

what will be the kinetic energy if the mass ismade four times and velocity is doubled

Join BYJU'S Learning Program