What would you observe in each of the following cases?
Water is added to the product formed, when aluminium is burnt in a jar of nitrogen gas.

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Solution

Aluminum $(Al)$ burnt in a jar of nitrogen gas $(N_{2})$ :
When aluminum is burnt in a jar of nitrogen gas, aluminum nitride $(AlN)$ is formed.
$2 Al (s) + N_{2} (g) \to 2 AlN (s)$
Addition of water to aluminum nitride $(AIN)$ :
Aluminum nitride undergo hydrolysis and is decomposed by water to give ammonia gas.
$AlN (s) + 3 H_{2} O (l) ⟶ Al (OH)_{3} (aq) + {NH}_{3} (g) ↑$
Therefore, when aluminum is burnt in a jar of nitrogen gas, aluminum nitride is formed which reacts with water to release ammonia gas.

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