When a metal - X- is treated with cold water- it gives a basic salt - Y- with molecular formula - XOH- -molecular mass - - 40- and liberates nbsp-a gas - Z- which easily catches fire- Identify - X-Y- and - Z- Y- -160-is - NaOH- - Z- is - H-2- Y- is - NaOH- - Z- is - CO-2- Y- is - KOH- - Z- is - H-2- Y- is - KOH- - Z- is - CO-2-

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When a metal ...

Question

When a metal $X$ is treated with cold water, it gives a basic salt $Y$ with molecular formula $X O H$ (molecular mass $= 40$ ) and liberates a gas $Z$ which easily catches fire. Identify $X, Y$ and $Z$ .

Y

N a O H

Z

H_{2}

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Y

N a O H

Z

C O_{2}

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Y

K O H

Z

H_{2}

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Y

K O H

Z

C O_{2}

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Solution

The correct option is A $Y$ is $N a O H$ , $Z$ is $H_{2}$
The salt is $N a O H$ and its molar mass can be calculated as follows:
$N a (23) + O (16) + H (1) = 23 + 16 + 1 = 40$

It is clear that X is sodium, Y is sodium hydroxide and Z is hydrogen. The reaction can be shown by following equation: $2 N a + 2 H_{2} O \to 2 N a O H + H_{2} + Heat$

Hydrogen is a highly inflammable gas and hence it easily catches fire.

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When a metal X is treated with cold water, it gives a basic salt Y with molecular formula XOH (molecular mass =40) and liberates a gas Z which easily catches fire. Identify X,Y and Z.

When a metal $X$ is treated with cold water, it gives a basic salt $Y$ with molecular formula $X O H$ (molecular mass $= 40$ ) and liberates a gas $Z$ which easily catches fire. Identify $X, Y$ and $Z$ .