When $C O_{2}$ is passed through lime water, it turns milky. The milkiness is due to:

C a C O_{3}

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C a (O H)_{2}

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H_{2} O

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C O_{2}

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Solution

The correct option is B $C a C O_{3}$
$C O_{2}$ dissolves in water to form carbonic acid.
$C O_{2} (g) + H_{2} O (l) ⟶ H_{2} C O_{3} (a q)$
Lime water, which is calcium hydroxide, neutralizes the carbonic acid. The product is calcium carbonate, an insoluble, white salt. Hence the milkiness of the solution.
$H_{2} C O_{3} (a q) + C a (O H)_{2} (a q) ⟶ C a C O_{3} (s) + 2 H_{2} O (l)$
Overall, this reaction can be represented as:
$C a (O H)_{2} + C O_{2} ⟶ C a C O_{3} + H_{2} O$

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