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Question

When ethyl iodide and propyl iodide react with Na in the presence of ether, they form .

A
One alkane
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B
Three alkanes
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C
Four alkanes
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Solution

The correct option is B Three alkanes

Let's recall Wurtz Reaction.

Alkylhalide reacts with metallic sodium in the presence of dry ether to form symmetrical alkanes containing double the number of C atoms present in the alkyl halide.

RX+2Na+XRDry−−etherRR+2NaX

CH3Br+2Na+BrCH3CH3CH3+2NaBr

Now,

C2H5l+2Na+C3H7lDry−−etherC2H5C3H7+2Nal

Pentane

C2H5l+2Na+C2H5lDry−−etherC2H5C2H5+2Nal

Butane

C3H7l+2Na+C3H7lDry−−EtherC3H7C3H7+2Nal

Hexane


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