When few pieces of iron are dropped into a blue coloured copper sulphate solution, the blue colour fades and eventually turns into light green due to the formation of:

F e_{2} (S O_{4})_{3}

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F e_{2} S O_{3}

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F e S O_{4}

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F e S O_{2}

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Solution

The correct option is C $F e S O_{4}$
When few pieces of iron are dropped into a blue coloured copper sulphate solution, the blue colour fades and eventually turns into light green due to the formation of ferrous sulphate.

$C u S O_{4} (B l u e) (a q) + F e (s) \to F e S O_{4} (G r e e n) (a q) + C u (s)$

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When few pieces of iron are dropped into a blue coloured copper sulphate solution, the blue colour fades and eventually turns into light green due to the formation of:

The correct option is C FeSO4When few pieces of iron are dropped into a blue coloured copper sulphate solution, the blue colour fades and eventually turns into light green due to the formation of ferrous sulphate. CuSO4(Blue)(aq)+Fe(s)→FeSO4(Green)(aq)+Cu(s)