When $H_{2}S$ is passed through nitric acid solution the products formed are-

Q. When $H_{2}S$ is passed through nitric acid solution the products formed are-

Q. When $H_{2}S$ gas is passed through nitric acid, the product is:

Q. Among the following allotropic forms of sulphur, the number of allotropic forms, which will show paramagnetism is _______
$\left(A\right)\alpha -sulphur$
$\left(B\right)\beta -sulphur$
$\left(C\right)S_2-form$

Q. What happens when $H_{2}S$ gas is passed through nitric acid?

Q. Assertion :Sometimes it happens that when $H_{2}S$ gas is passed into solutions in .dil. HCl, yellowish white turbidity appears. Reason: The yellowish turbidity is due to colloidal sulphur, formed by oxidation of $H_{2}S$ by the presence of $N{O}_3^{-}$ or $N{O}_2^{-}orS{O}_3^{2-}$
$H_{2}S+HN{O}_3⟶S$(colloidal)
Before passing $H_{2}S$ gas, solution is boiled so as to decompose these radicals.