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Calcination

When K_2...

Question

When $K_{2} C r_{2} O_{7}$ crystals are heated with conc. $H C l$ , the gas evolved is :

O_{2}

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C l_{2}

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C r O_{2} C l_{2}

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H C l

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Solution

The correct option is B $C l_{2}$
Chlorine can be prepared as follows:
$K_{2} C r_{2} O_{7} + 14 H C l H e a t - -- \to 2 K C l + 2 C r {C l}_{3} + 7 H_{2} O + 3 {C l}_{2}$
Hence the chlorine gas is liberated .

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