When manganese dioxide is treated with $H C l$ ,oxidation state of chlorine on the product side is:

- 1

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0

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+ 1

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+ 3

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Solution

The correct options are
A $- 1$
B $0$
$M n O_{2} + 4 H C l ⟶ M n {C l}_{2} + {C l}_{2}$
Oxidation state of $C l$ on the product side is $- 1, 0$

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Similar questions

Chlorine is prepared in the laboratory by treating manganese dioxide (MnO₂) with aqueous hydrochloric acid according to the reaction

4HCl₍_aq₎ + MnO₂₍_s₎ → 2H₂O₍_l₎ + MnCl₂₍_aq₎ + Cl₂₍_g₎

How many grams of HCl react with 5.0 g of manganese dioxide?

M n O_{2}

(M n O_{2})

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