When $S O_{2}$ is passed through an acidic solution of potassium dichromate, chromium sulphate is formed. The change in oxidation number of chromium is:

+6 to +2

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+6 to +3

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+5 to +3

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+6 to +4

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Solution

The correct option is B +6 to +3
$K_{2} C r_{2} O_{7} + 3 S O_{2} + H_{2} S O_{4} ⟶ K_{2} S O_{4} + C r_{2} (S O_{4})_{3} + H_{2} O$
Here, the change in oxidation state is from +6 to +3.

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