Which among the following has the highest normality-0-5 M sulphuric acid1 N phosphoric acid-2 moles of NaOH per 1000 ml of solution8 g of KOH per 100 ml of solution

The correct option is C 2 moles of NaOH per 1000 ml of solutionN = no.of equivalents/Volume of solution(L) N of KOH = [ 8/56 ]/0.1 = 1.43 N N of H_2SO_4 = M × ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Ideal Gas Equation

Which among t...

Question

Which among the following has the highest normality?

8 g of KOH per 100 ml of solution

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5 M sulphuric acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 N phosphoric acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 moles of NaOH per 1000 ml of solution

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 2 moles of NaOH per 1000 ml of solution
$N = \frac{no.of equivalents}{Volume of solution(L)}$
N of KOH = $\frac{[\frac{8}{56}]}{0.1} = 1.43 N$
N of $H_{2} S O_{4}$ = M $\times$ n factor = $0.5 \times 2 = 1 N$
equivalents of NaOH = moles $\times$ n factor
= $2 \times 1 = 2$ eq
N of NaOH = $\frac{2}{1} = 2$ N

Suggest Corrections

Similar questions

Q. What is the strength in gram per litre of a solution of sulphuric acid, 12 mL of which neutralises 15 mL of

\frac{M}{10}

NaOH solution?

Q. What is the strength in

g

per

l i t r e

of a solution of sulphuric acid,

12 m L

of which neutralise

15 m L

N / 10

sodium hydroxide solution?

Q. When

100 mL 1 N N a O H

solution and

10 mL

10 N

sulphuric acid solution are mixed together, the resulting solution will be:

Q. A mono basic acid is dissociated to 25% in 0.1 N solution. When 100 mL of the acid is neutralized by 0.1

N

KOH solution, heat evolved was 120 cal. Heat of dissociation per mole of acid in kcal is (nearest integer)________.

Q. What volume of a

0.345 M

phosphoric acid solution is required to neutralize

125 mL

of a

0.123 M K O H

solution?

Join BYJU'S Learning Program

Which among the following has the highest normality?

The correct option is D 2 moles of NaOH per 1000 ml of solutionN=no.of equivalentsVolume of solution(L) N of KOH = [856]0.1=1.43N N of H2SO4 = M × n factor = 0.5×2=1N equivalents of NaOH = moles × n factor = 2×1=2eq N of NaOH = 21=2N