Which among the following is wrong about isodiapheres?

The correct option is A All are correct
$-$2 nuclides are called isodiaphers if they both have the same difference between the number of neutrons and protons.

$-$${}_Z^{A}X\underrightarrow{-\alpha }{}_{Z-2}^{A-4}Y$

$\Rightarrow$(A-Z)-Z (A-4-(Z-2)) - (Z-2) [Difference b/w the no. of neutrons and protons]

$A-2Z=A-2Z$

$\therefore$Nuclide and its decay product after $\alpha$-emission are isodiaphers.