The correct option is C Ni(CO)4]
In the case of [Ni(CO)4] the Ni is not charged and hence the configuration is 3d84s2, Now since CO is a strong ligand hence the pairing of electrons take place and Therefore the configuration changes to 3d104s0 following this the CO donates its electrons to 4s and 4p subshell and hence the hybridization of [Ni(CO)4] is sp3 and the geometry is tetrahedral.