Which of the following has the maximum number of atoms?

The correct option is B $44.8$ litres of $N{H}_3$
1 mole of any gas occupies $22.4L$ volume.

Number of moles in $56LS{O}_2=\frac{56}{22.4}=2.5mole$

$S{O}_2$ has $3atoms$ per molecule.

Number of atoms in molecule$=3\times 2.5=7.5moles$

Number of moles in $44.8LN{H}_3=\frac{44.8}{22.4}=2mole$

$N{H}_3$ has $4atoms$ per molecule.

Number of atoms in molecule$=4\times 2=8moles$

Number of moles in $33.6LC{H}_4=\frac{33.6}{22.4}=1.5mole$

$C{H}_4$ has $5atoms$ per molecule.

Number of atoms in molecule$=5\times 1.5=7.5moles$

Number of moles in $56LCO=\frac{56}{22.4}=2.5mole$

$CO$ has $2atoms$ per molecule.

Number of atoms in molecule$=2\times 2.5=5moles$

Therefore maximum atoms are present in $44.8L$ of $N{H}_3$