Which of the following hydrolysis product is not common in hydrolysis of $Xe{F}_2\text{and}Xe{F}_4$ respectively?

The correct option is D $Xe{O}_3$
Hydrolysis of $Xe{F}_2$ gives
$2Xe{F}_2+2H_{2}O\stackrel{}{\to }2Xe+O_2+4HF$

Hydrolysis of $Xe{F}_4$ gives
$6Xe{F}_4+12H_{2}O\stackrel{}{\to }4Xe+2Xe{O}_3+24HF+3O_2$

The product which is not common in above hydrolysis is $Xe{O}_3$.
Hence, the correct answer is option (d).