Which of the following ions has a magnetic moment of 5.93 BM?

[At . No. : V = 23 , Cr = 24, Mn = 25, Fe = 26]

M n^{2 +}

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F e^{2 +}

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C r^{2 +}

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V^{3 +}

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Solution

The correct option is A $M n^{2 +}$
Magnetic moment $= \sqrt{n (n + 2)} B M$

where n = number of unpaired electrons

$5.93 = \sqrt{n (n + 2)}$

$n = 5$

$M n^{2 +}$ ion $(3 d^{5})$ has $5$ unpaired electrons and thus, magnetic moment is $5.93 B M$

Hence, option $A$ is correct.

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C r^{2 +}, M n^{2 +}, F e^{2 +} a n d N i^{2 +} a r e 3 d^{4}, 3 d^{5}, 3 d^{6} a n d 3 d^{8}

C r = 24, M n = 25, F e = 26, N i = 28

C r^{2 +}, M n^{2 +}, F e^{2 +} and C o^{2 +} are d^{4}, d^{5}, d^{6} and d^{7}

C r = 24, M n = 25, F e = 26, C o - 27

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