Which of the following transition elements will exhibit the least enthalpy of atomisation?

Z n

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S c

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C o

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M n

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Solution

The correct option is A $Z n$
Outer electronic configuration of $Z n = 3 d^{10} 4 s^{2}$ .
Outer electronic configuration of $S c = 3 d^{1} 4 s^{2}$ .
Outer electronic configuration of $C o = 3 d^{7} 4 s^{2}$ .
Outer electronic configuration of $M n = 3 d^{5} 4 s^{2}$ .

In general, the greater the number of unpaired electrons, the stronger is the resultant bonding and hence, higher is the enthalpy of atomisation. In the $3 d$ series, from $S c$ to $Z n$ , $Z n$ has no unpaired electrons. Hence, it exhibits weak interactions and thus possesses the least enthalpy of atomisation.

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