You visited us 18 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Race of Rollers

Which one is ...

Question

Which one is correct for a cyclic process as shown in the figure?

d U = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

q = - w

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

314 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

31.4 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A $q = - w$
C $d U = 0$
D $314 J$
$(a, b, c)$ For a cyclic process, $d U = 0$
$∴$ $q = Δ U + (- w)$
$q = - w$
Also, $w = A r e a c o v e r e d b y s p h e r e$
$= π r^{2} = π \times {[\frac{(V_{2} - V_{1})}{2}]}^{2}$
$= \frac{π \times (20)^{2}}{2^{2}}$
$= 100 π = 100 \times 3.14 = 314 J$

Suggest Corrections

Similar questions

Q. Which one of the following(s) is/are correct for a cyclic process as shown in figure?

Q. A gas is undergoing a cyclic process as shown in figure, where

P_{0} = 2 bar

and

V_{0} = 7 m^{3}

. Find the workdone (

W

) by the gas and heat (

Q

) released by the gas in one cycle.

Q. One mole of Helium gas undergoes a reversible cyclic process ABCDA as shown in the figure.
Assuming gas to the ideal, answer the following questions:

What is the value of ‘q’ for the overall cyclic process?

Q. One mole of an ideal monoatomic gas is carried through the reversible cyclic process as shown in figure. Then which statements are correct?

Q. A cyclic process on an ideal monatomic gas is shown figure. The correct statement is

Join BYJU'S Learning Program

Which one is correct for a cyclic process as shown in the figure?

COURSES

EXAMS

CLASSES

EXAM PREPARATION

RESOURCES

COMPANY

FOLLOW US

FREE TEXTBOOK SOLUTIONS

STATE BOARDS

FOLLOW US

Which one is correct for a cyclic process as shown in the figure?

The correct options are A q=−w C dU=0 D 314J(a,b,c) For a cyclic process, dU=0 ∴ q=ΔU+(−w)q=−wAlso, w=Areacoveredbysphere=πr2=π×[(V2−V1)2]2=π×(20)222=100π=100×3.14=314J

COURSES

EXAMS

CLASSES

EXAM PREPARATION

RESOURCES

COMPANY

FOLLOW US

FREE TEXTBOOK SOLUTIONS

STATE BOARDS

FOLLOW US