Write a balanced chemical equation for the following:
Action of concentrated Sulphuric acid on Sulphur.

Part 1: Balanced equation:-

1. When concentrated Sulphuric acid is added with Sulphur, Sulphur dioxide and water are formed as the product.
2. Balanced equation of the reaction- $\underset{\left(\mathrm{Sulphur}\right)}{\mathrm{S}\left(\mathrm{s}\right)}+\underset{(\mathrm{conc}.\mathrm{sulphuric}\mathrm{acid})}{2{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)}\to \underset{(\mathrm{Sulphur}\mathrm{dioxide})}{3{\mathrm{SO}}_2\left(\mathrm{g}\right)}+\underset{\left(\mathrm{Water}\right)}{2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}$

Final answer:- Action of concentrated Sulphuric acid on Sulphur

$\underset{\left(\mathrm{Sulphur}\right)}{\mathrm{S}\left(\mathrm{s}\right)}+\underset{(\mathrm{conc}.\mathrm{sulphuric}\mathrm{acid})}{2{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)}\to \underset{(\mathrm{Sulphur}\mathrm{dioxide})}{3{\mathrm{SO}}_2\left(\mathrm{g}\right)}+\underset{\left(\mathrm{Water}\right)}{2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}$