Write all possible $3 - digit$ numbers that can be formed by the digits $1, 3$ and $7$ , using each digit only once in each number.

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Solution

Here we have to form $3 - digit$ numbers using digits $1, 3$ and $7$ using each digit only once in each number
Keeping $1$ at ones place, $3 - digit$ numbers are $371 and 731$
Keeping $3$ at ones place, $3 - digit$ numbers are $173 and 713$
Keeping $7$ at ones place, $3 - digit$ numbers are $137 and 317$
Hence the required numbers are $371, 731, 173, 713, 137$ and $317$

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