Write balanced chemical equations for each of the following :
Action of dilute sulphuric acid on potassium hydroxide.

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Solution

$Potassium hydroxide (KOH)$ is reacted with $Sulphuric acid (H_{2} {SO}_{4})$ to form $Potassium sulphate (K_{2} {SO}_{4})$ and $Water (H_{2} O)$ .
The following chemical reaction takes place when hydrogen gas interacts with nitrogen to form ammonia in presence of a catalyst at $773 k$ .
Given chemical equation is:
$\underset{Potassium hydroxide}{KOH (s)} + \underset{Sulphuric acid}{H_{2} {SO}_{4} (aq)} \to \underset{Potassium sulphate}{K_{2} {SO}_{4} (s)} + \underset{Water}{H_{2} O (aq)}$
Balancing the above equation, we get
$\underset{Potassium hydroxide}{2 KOH (s)} + \underset{Sulphuric acid}{H_{2} {SO}_{4} (aq)} \to \underset{Potassium sulphate}{K_{2} {SO}_{4} (s)} + \underset{Water}{2 H_{2} O (aq)}$

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Write balanced chemical equations for each of the following : Action of dilute sulphuric acid on potassium hydroxide.

Write balanced chemical equations for each of the following :
Action of dilute sulphuric acid on potassium hydroxide.