Write balanced equation and name the product formed when cupric oxide reacts with nitric acid.

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Solution

Reaction between cupric oxide and dilute nitric acid:
When cupric oxide reacts with dilute nitric acid, it forms copper nitrate and water.
The balanced chemical reaction can be represented as:
$\underset{}{\underset{Cupric oxide}{CuO (s)}} + \underset{}{\underset{Nitric acid}{2 {HNO}_{3} (l)}} \to \underset{}{\underset{Copper nitrate}{Cu {({NO}_{3})}_{2} (s)}} + \underset{}{\underset{Water}{H_{2} O (l)}}$

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Write balanced equation and name the product formed when cupric oxide reacts with nitric acid.

Reaction between cupric oxide and dilute nitric acid:When cupric oxide reacts with dilute nitric acid, it forms copper nitrate and water.The balanced chemical reaction can be represented as:CuO(s)Cupricoxide+2HNO3(l)Nitricacid→Cu(NO3)2(s)Coppernitrate+H2O(l)Water