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Question

Write balanced equations for the following reactions:
(a) reduction of copper oxide by hydrogen.
(b) reduction of iron (III) oxide by carbon monoxide.
(c) reduction of lead (II) oxide by carbon.

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Solution

(a) On heating copper oxide in the presence of hydrogen gas, it gets reduced to copper metal and water.​
CuO + H2 Heat Cu + H2OCopper oxide Hydrogen gas Copper Water

(b) On heating iron (III) oxide in the presence of a reducing agent such as carbon monoxide, it reduces to iron and carbon dioxide gas is liberated in the process.​
Fe2O3 + 3CO Heat 2Fe + 3CO2Iron (III) oxide Carbon monoxide Iron Carbon dioxide

(c) On heating lead (II) oxide with carbon as a reducing agent​, it gets reduced to lead and carbon monoxide gas is liberated in the process.​
PbO + C Heat Pb + COLead (II) oxide Carbon Lead Carbon monoxide

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