Write the balanced equation of reduction of copper oxide by hydrogen.

• When Copper oxide reacts with hydrogen gas, the Copper oxide is reduced to copper metal, and water is formed.
• The chemical equation for the reaction can be written as:
• $$\begin{gathered} \mathrm{CuO}\left(\mathrm{s}\right)+{\mathrm{H}}_2\left(\mathrm{g}\right)\to \mathrm{Cu}\left(\mathrm{s}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right) \\ (\mathrm{Copper}(\mathrm{Hydrogen})(\mathrm{Copper})(\mathrm{Water}\left) \\ \mathrm{oxide}\right) \end{gathered}$$