Write the increasing order of basic character of $M g O, S r O, K_{2} O, N i O$ and $C s_{2} O$ :

C s_{2} O < K_{2} O < S r O < M g O < N i O

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C s_{2} O > K_{2} O > S r O > M g O > N i O

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C s_{2} O > K_{2} O > M g O > S r O > N i O

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K_{2} O > C s_{2} O > S r O > M g O > N i O

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Solution

The correct option is B $C s_{2} O > K_{2} O > S r O > M g O > N i O$
The proper increasing order of basic character is $N i O < M g O < S r O < K_{2} O < C s_{2} O$ .
Generally metal oxides are basic in nature.
The basic character of oxides increases when we move down the group. So, $K_{2} O < C s_{2} O$ and $M g O < S r O$ .
Again, basic character of the oxides decreases as we move from left to right across a period, thus $N i O$ has the least basicity.

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