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Question

∫x+3x+42exdx=

(a) exx+4+C

(b) exx+3+C

(c) 1x+42+C

(d) exx+42+C

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Solution

(a) exx+4+C

LetI=∫x+3x+42exdx⇒∫x+4-1x+42exdx⇒∫1x+4-1x+42exdxAs,weknowthat∫exfx+f'xdx=exfx+C∴I=exx+4+C

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